![]() ![]() If it becomes equal to ‘k’ at any moment, we can reset it back to zero. If we iterate back in string s, we can maintain a counter that keeps a count of the number of characters added in a group. This is important because we know except for the first group, all other groups must have exactly ‘k’ letters in them. It is intuitive that we should create a new string while iterating backward in string s(input). Furthermore, the groups must be separated by ‘-‘(dash) and have only uppercase letters. We are also given an integer K, and the goal is to format the string such that every group contains exactly K characters, except for the first one, which is allowed to characters less than K. Initially, the string is separated into N + 1 groups(words) by N dashes in between. In the problem “License Key Formatting”, the input consists of a string of characters, representing a license key. Complexity Analysis of License Key Formatting Leetcode Solution.Implementation of License Key Formatting Leetcode Solution.
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